解方程:2/3[3/2(3x+1)-6x+3]-2=x+1用一元一次方程解，要详细过程，谢谢了！！急用

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解烂派团档
2/3[3/饥或贺2(3x+1)-6x+3]-2=x+1
2/3×3/2(3x+1)-2/3×6x+3×2/3-2=x+1
3x+1-4x+2-2=x+1
-x+1=x+1
2x=0
x=0

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