不定积分e^x-1/（e^x+1）dx=

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e^x=y
∫氏和（e^x-1) / (e^x +1)dx
=∫（y-1) / (y +1)/仔核饥念返ydy
=∫（2/(y+1)-1/y)dy
=2ln(y+1)-ln(y)
=2ln(e^x+1)-ln(e^x)
=2ln(e^x+1)-x

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