怎么走天津大学设方程e^(x+y)+sin(xy)=1确定的隐函数为y=y(x),求y'和y'|x=0第1个回答:吉禄学阁高粉答主2009-02-22教育达人关注



第1个回答:

吉禄学阁高粉答主2009-02-22教育达人关注e^(x+y)+sin(xy)=1e^(x+y)*(1+y')+cos(xy)(y+xy')=0y'*[e*(x+y)+xcos(xy)]=-[ycos(xy)+e^(x+y)]y'=-[ycos(xy)+e^(x+y)]/[e*(x+y)+xcos(xy)]x=0,求出y=0,代入上式,得到y'(x=0)=-1.