函数f(x)=根号下x+1/x-2的定义域是集合A,集合B={x丨(x-a)[x-(a+1)>0]}求集合A B

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(x+1)/(x-2)>=0 x-2≠0 A={x|x>汪胡2或者x<=-1} (x-a)(x-a-1)>培陵纤0 B={x|x>a+1或配仿者x<a}

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