求极限limx趋向于0(1/e^x-1)-(1/x)

---

用等价无穷运蔽铅小替换和洛并芹必达法则，原式=lim(x→0)(x-e^x+1)/(x(e^x-1))=lim(x→0)(x-e^x+1)/x^2=lim(x→0)(1-e^x)/(2x)=-1/2lim(x→0)(e^x-1)/旁好x=-1/2

---