高数大神你给详解我给好评 1

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15 原式 = ∫{[2x - 2(72)^(1/6)x^(5/6) + 9^(1/羡孝山3)x^(2/3)]/兄中x}dx
= ∫[2 - 2(72)^(1/6)x^(-1/6) + 9^(1/3)x^(-1/3)]dx
= 2x - (12/5)(72)^(1/6)x^(5/6)+ (3/2)9^(1/3)x^(2/慎此3)+ C

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将上面的平方项展开就行了

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