求不定积分∫（2x²+3e∧x+5sinx）dx

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解：
∫陆租友型盯 (2x² + 3e^x + 5sinx) dx
= 2 ∫ x² dx + 3 ∫ e^x dx + 5 ∫ sinx dx
= 2 (1/3) x³ + 3 e^x + 5 (-cosx) + C
= 2/3 x³ + 3e^x - 5cosx + C

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∫（2x²+3e∧x+5sinx）dx

=2x³/3+3e∧x-5cosx

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