设随机变量X与Y相互独立，且X~N(2，1),Y~N(-2，4),Z=3X-2Y+4，求：D(Z) 与 P{Z<=9}

---

Z还是正态分布,利段告派用公握贺式
E(aX+bY)=aE(X)+bE(Y)
D(aX+bY)=a²D(X)+b²D(Y)

由已友孝知得E(X) = 2, D(X) = 1,E(Y) = -2, D(Y) = 4,则：
E(Z) = E(3X-2Y+4) = 3E(X) - 2E(Y) + E(4) = 14
D(Z) = D(3X-2Y+4) = 9D(X) + 4D(Y) + 0 = 25
所以 Z~N(14,25)
P{Z<=9} = P{(z-14)/5 <= (9-14)/5} = φ(-1) = 1-φ(1) = 0.16

---

Z=3X-2Y+4

E(Z)=E(3X-2Y+4)
=E(3X)-E(2Y)+E(4)
=3*2-2*2+4
=9
D(Z)=D(3X-2Y+4)
=D(3X)+D(2Y)+D(4)
=9*1+4*4
=25
P{Z<扰仔陆缓顷戚做=9}

=P0.5

---