sinx+tanx/1+cosx= 化简吧

(sinx+tanx)/(1+cosx)

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解答：陵竖
sinx+tanx/1+cosx
=(sinx+sinx/cosx)/(1+cosx)
=(sinxcosx+sinx)/[cosx(1+cosx)]
=sinx(cosx+1)/尺如大[cosx(1+cosx)]
=sinx/橡禅cosx
=tanx

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=sinx+cosx/sinx+cosx=sin²x+cosx+sinx·cosx，，，然后怎么化啊

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