若x、y为实数,y<根号x-1+根号1-x+1/2,化简1/y-1×根号1-2y+y²

---

根号下扮纯则x-1>=0,x>=1
1-x>纯码=0,x<=1
统统是成立则x=1
所以x-1=1-x=0
所以y=0+0+1/2=1/做缺哪2

所以原式=1/(y-1)×√(1-y)²
=1/(y-1)×|1-y|
=1/(-1/2)×|1/2|
=-1

---

分不清楚根号后边是谁

---