已知a、b互为相反数，c、d互为负倒数，求√（a²+b²）+cd的立方根

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解：
√搏逗（a²+b²厅轿）+（cd）^(1/3)
=√（a²+（-a）基伏卖² +（c*（-1/c））^(1/3)
=√2a² -1
=|a|√2 -1

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