若x的平方+y的平方-2x-6y+10=0,求分式x的平方-y的平方/xy的值.

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x的平方+y的平方-2x-6y+10=0
=>
x^2 - 2x + 1 -1 + y^2 - 6y + 9 - 9 + 10 =0
=>
(x-1)^2 + (y-3)^2 = 0
两个非负数樱渗的肆世和为0
所裂颂肢以
x-1 = 0 且y-3=0
那么
x=1， y=3
所以(x^2-y^2)/xy = (1 - 9)/3 = -8/3

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x^2+y^2-2x-6y+10=0
→模简（x-1）^2+(y-3)^2=0
则x=1，y=3
(x^2-y^2)/xy=(1^2-3^2)/1×3=-8/3
不懂百度HI我，祝愉旦埋裤快液启

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x的平方+y的平陪核方-2x-6y+10=(x-1)^2+(y-3)^2=0
x=1 y=3
x的平方旦源-y的平方/芦迟掘xy=(1-9)/3=-8/3

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