y=log2^[1/(x+1)]+log2^(x^2-1)的反函数（过程、、）

---

y=log2^[1/(x+1)]+log2^(x^2-1)=log2^[1/(x+1)*(x^2-1)=log2^[1/旁灶(x+1)*(x-1)（x+1）=log2^(x-1)
反盯败函运则扮数x=log2^(y-1)
所以y-1=2^x
y=2^x+1

---