求极限lim(x->0, ((1+tanx) /(1+sinx))^(1/x^3))

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看悄则不码运尺清可迟高放大

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正确弯判解答早闹兄陆袭如图

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先求对轿裤毁数闭备的极纯颤限
limx^3ln(1+tanx)/ln(1+sinx)
=limx^3*tanx/sinx (ln(1+tanx)~tanx,ln(1+sinx)~sinx)
=linx^3*x/x=0
故原极限=e^0=1

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1000

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