error : expected primary-expression before ' || ' token error : expected ' : ' before ' printf '

# include <math.h>
# include <stdio.h>

int main () {
int i, j, num;
int p, q, flagp, flagq;
printf("Please input a plus integer: ");
scanf("%d", &num);

// 代码 (num%2)!=0 表示num 不能被2整除
if((num%2)!=0)||(num<=4)
printf("input data error!\n");

else {
p = 1;
// do－while 循环
do {
p = p + 1;
q = num - p;
flagp = 1;
flagp = 1;
// for 循环体
for(i = 2; i <= (int)(floor(sqrt((double)(p)))); i++) {
if((p % i == 0)) {
flagp = 0;
break;
}
}
// while 循环体
j = 2;
while(j <= (int)(floor(sqrt((double)(q))))) {
if((q % j) == 0) {
flagq = 0;
break;
}
j++;
}
} while(flagp * flagq == 0);

printf("%d = %d + %d\n", num, p, q);
}
}

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没怎么细瞎顷看楼主的程序，不过楼主的错误显而易见，error : expected primary-expression before ' || ' token error : expected ' : ' before ' printf '已经说明错误出在||附近，printf之亏神罩前
if((num%2)!=0)||(num<=4)少了右括号。
其实num%2和num<=4也不用再加括号，if的括号就够了。
改过后应为销闹if((num%2)!=0)||(num<=4))

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#include <stdio.h>
void print_array(int a[],int arraysize);
int max_array(int a[],int arraysize);

int main(void)
{
int j,a[10]=;
for(j=0;j<10;j++)
print_array(a,10); \\这里改斗败源为调用数组名就可以了
max_array(a,10); \\这里枯含改为调用数组名
return 0;
}

void print_array(int a[],int arraysize)
{
static int i=0;
printf("%d",a[i]);
i++;

}

int max_array(int a[],int arraysize)
{
int i,t;
for(i=0;i<arraysize;i++)
{
if(a[i]>a[i+1])
{
t=a[i];
a[i]=a[i+1];
a[i+1]=t;
}
}
printf("The max value is %d"空态,a[arraysize-1]);
return 0;
}
请参考

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