若x=根号5/2,求根号x+1-根号x-1/根号x+1+根号x-1 + 根号x+1+根号x-1/根号x+1-根号x-1 的值

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[√(x+1)-√(x-1)]/[√(x+1)+√(x-1)] + [√桥野(x+1)+√(x-1)]/[√(x+1)-√(x-1)]

=[√(x+1)-√(x-1)]^2/[√(x+1)+√(x-1)][√码禅(x+1)-√(x-1)]
+ [√(x+1)+√(x-1)]^2/[√(x+1)-√(x-1)][√(x+1)+√(x-1)]}

=[√(x+1)-√(x-1)]^2/2
+ [√(x+1)+√(x-1)]^2/2

=[x+1+x-1-2√(x+1)√(x-1)]/2
+[x+1+x-1+2√(x+1)√(x-1)]/2

=[2x-2√(x+1)√(x-1)]/敏模喊2+[2x+2√(x+1)√(x-1)]/2

=x-√(x+1)√(x-1)+x-√(x+1)√(x-1)

=2x

=2*√5/2

=√5

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你应该用括号将运算符号再说明一下，要不不明白的。

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用式子表示，你这样又没括号，怎么看得懂

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