因式分解a2-b2+2b-1 (a2d2为a的平方b的平方)

求过程谢谢各位大侠

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a2-b2+2b-1
＝a2-(b2-2b+1)
=a2-(b-1)2
=(a-b+1)(a+b-1)

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a^2-b^2+2b-1
=a^2-(b^2-2b+1)
=a^2-(b-1)^2
=(a+b-1)(a-b+1)

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a2-b2+2b-1
=a2-(b2-2b+1)
=a2-(b-1)2
=(a+b-1)(a-b+1)

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a2-b2+2b-1
=a2-(b2-2b+1）
=a2-(b-1)2
=(a+b-1)(a-b+1)

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