先化简再求值3xy^2-[xy-2(2x-3\2x^2y)+32xy^2]+3x^2y,其中x=3,y=-3\1

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32错羡肢判了饥虚吧，就是3

原式=3xy^2-(xy--4x+3x^2y+3xy^2)+3x^2y
=3xy^2-xy+4x-3x^2y-3xy^2+3x^2y
=-xy+4x
=-3*（兄改-3/1）+4*3
=13

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